一、需求
我們有三張表，我們需要分類統計一段時間內抗生素的不同藥敏結果，即 report_item_drugs 表的 drugs_result， 在不同項目project_name 和不同抗生素 antibiotic_dict_name 下的占比，并將藥敏結果顯示在行上，效果如下：
三張原始表（僅取需要的字段示例），分別是：
報告表
項目表
抗生素表（藥敏結果drugs_result為一列值）
二、實現
1、按照項目、抗生素分組求出檢出的總數
SELECT
A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數
FROM
(
SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
) A
GROUP BY A.project_name,A.antibiotic_dict_name
2、按照項目、抗生素、藥敏結果求出不同藥敏結果數量
SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result>'', d.drugs_result, '未填寫') AS drugs_result,COUNT(d.id) AS 數量
FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
3、將兩個結果關聯到一起
SELECT
BB.project_name,BB.antibiotic_dict_name,BB.drugs_result,BB.`數量`,AA.`檢出總數`
FROM
(
SELECT
A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數
FROM
(
SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
) A
GROUP BY A.project_name,A.antibiotic_dict_name
) AA
RIGHT JOIN
(
SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result>'', d.drugs_result, '未填寫') AS drugs_result,COUNT(d.id) AS 數量
FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
)BB ON AA.project_name=BB.project_name AND AA.antibiotic_dict_name=BB.antibiotic_dict_name
WHERE AA.`檢出總數`>''
4、一般來說，到上一步不同藥敏數量和總數都有了，可以直接求比例了
但是，我們需要的是將藥敏顯示到行上，直接求比不符合需求，所以我們需要將列轉換為行
我們借助于case when實現行列轉換，并將藥敏結果根據字典轉為方便閱讀的漢字
SELECT
C.project_name 項目名稱,C.antibiotic_dict_name 抗生素名稱,C.`檢出總數`,
SUM(CASE C.`drugs_result` WHEN 'D' THEN C.`數量` ELSE 0 END ) AS '劑量依賴性敏感',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'D' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '劑量依賴性敏感比率',
SUM(CASE C.`drugs_result` WHEN 'R' THEN C.`數量` ELSE 0 END ) AS '耐藥',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'R' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '耐藥比率',
SUM(CASE C.`drugs_result` WHEN 'S' THEN C.`數量` ELSE 0 END ) AS '敏感',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'S' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '敏感比率',
SUM(CASE C.`drugs_result` WHEN 'I' THEN C.`數量` ELSE 0 END ) AS '中介',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'I' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '中介比率',
SUM(CASE C.`drugs_result` WHEN 'n1' THEN C.`數量` ELSE 0 END ) AS '非敏感',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'n1' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '非敏感比率',
SUM(CASE C.`drugs_result` WHEN 'N' THEN C.`數量` ELSE 0 END ) AS '無',
CONCAT(SUM(CASE C.`drugs_result` WHEN 'N' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '無比率',
SUM(CASE C.`drugs_result` WHEN '未填寫' THEN C.`數量` ELSE 0 END ) AS '未填寫',
CONCAT(SUM(CASE C.`drugs_result` WHEN '未填寫' THEN FORMAT(C.`數量`/C.`檢出總數`*100,2) ELSE 0 END),'%') AS '未填寫比率'
FROM
(
SELECT
BB.project_name,BB.antibiotic_dict_name,BB.drugs_result,BB.`數量`,AA.`檢出總數`
FROM
(
SELECT
A.project_name,A.antibiotic_dict_name,SUM(nums) AS 檢出總數
FROM
(
SELECT i.project_name,d.antibiotic_dict_name,d.drugs_result,COUNT(d.id) AS nums FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
) A
GROUP BY A.project_name,A.antibiotic_dict_name
) AA
RIGHT JOIN
(
SELECT i.project_name,d.antibiotic_dict_name,IF(d.drugs_result>'', d.drugs_result, '未填寫') AS drugs_result,COUNT(d.id) AS 數量
FROM `report` r
RIGHT JOIN report_item i ON r.id=i.report_id
RIGHT JOIN report_item_drugs d ON d.report_item_id=i.id
WHERE r.report_status=2 AND r.add_date BETWEEN '2020-01-01' AND '2020-12-30'
GROUP BY i.project_id,d.antibiotic_dict_id,d.drugs_result
)BB ON AA.project_name=BB.project_name AND AA.antibiotic_dict_name=BB.antibiotic_dict_name
WHERE AA.`檢出總數`>''
) C
GROUP BY C.project_name,C.antibiotic_dict_name;
5、查看結果，成功轉換
到此這篇關于mysql 行列轉換的示例代碼的文章就介紹到這了,更多相關mysql 行列轉換內容請搜索腳本之家以前的文章或繼續瀏覽下面的相關文章希望大家以后多多支持腳本之家！
您可能感興趣的文章:- 數據庫實現行列轉換(mysql示例)
- mysql 行列動態轉換的實現(列聯表,交叉表)
